3x=4x^2-15

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Solution for 3x=4x^2-15 equation:



3x=4x^2-15
We move all terms to the left:
3x-(4x^2-15)=0
We get rid of parentheses
-4x^2+3x+15=0
a = -4; b = 3; c = +15;
Δ = b2-4ac
Δ = 32-4·(-4)·15
Δ = 249
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{249}}{2*-4}=\frac{-3-\sqrt{249}}{-8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{249}}{2*-4}=\frac{-3+\sqrt{249}}{-8} $

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